HELP

Question

#include <iostream>
using namespace std;

int main() {
int i=1;
while(i<10)
{
cout << i << endl ;
if(i==5)
{
continue ;
}
++i;
}
return 0;
}

Output -
1
2
3
4
5
5
5
5
...

WHY THIS IS HAPPENING

Answer 1

when continue operator is execute then increment of counter (i++) is never happened. you need to do like that:
...
if(i==5) {
i++; continue; }
i++;
...

Answer 2

At i = 5 it will skip that particular iteration and continue to execute another iteration.

Here i is not incremented in if statement therefore i value will be 5 and it will create an infinite loop.

If your code is like this

if(i==5)
{
i++;
continue;
}

Than output will be

1 2 3 4 6 7 8 9

Answer 3

Right Indiegma.

first i++ than continue.

Answer 4

Thanks everyone

Answer 5

meet mehta.

if(i==5){
continue;
i++;}

your code will not work correctly, because i++ will be skipped always