Why the output is 7.How it is executed???

Question

check this code
https://code.sololearn.com/cfvk9hVaBQJS/?ref=app

Answer 1

It is called post incrementing. First assign the value to q and then increments it.

Answer 2

int i = 7 will create int variable with value of 7
and *q is pointer variable.

doing q = &i; will assign *q with address of i.

now on printf("%d", *q++);

will print the value of at address stored in q.
using q++ will print the value first and then it will increase the value.

so the output is 7.

Answer 3

It shows 7 because '++' after the variable executes after, if you want to execute it before you should use '++' before the variable.