/* it's time to delete some impenitent digit! Your job is to delete the digits of a given number that, within their name written in English, contain a given vowel. For an integer n, and a string delete being the vowel to search, return from a function: If the given vowel is not present in the name of any of the digits of n, the same n. If n has at least a digit that contains the given vowel in its name, the new integer obtained after the elimination of banned digits (as a natural number without leading zeros). If all digits of n are deleted, a string "Number DELETED". Examples: delete(143, "o") ➞ 3 # 1 = "One" contains "o" (deleted). # 4 = "Four" contains "o" (deleted). # 3 = "Three" is safe. delete(14266330, "e") ➞ 4266 # "One" contains "e" (deleted). # "Four", "Two" and "Six" are safe. # "Three" and "Zero" contain "e" (deleted). Challenge link - https://www.sololearn.com/post/306612/?ref=app */ #include #include #include using namespace std; string numstr[]{"zero", "one","two", "three", "four", "five", "six", "seven", "eight", "nine"}; auto Delete = [](size_t num, char vow) { string no{to_string(num)},res{""}; for_each(no.begin(),no.end(),[&](char ch){ if(numstr[ch-48].find(vow) == string::npos) res += ch; }); if(res.empty()) res = "Number DELETED\n"; cout << "Delete(" << num << ", " << "\'" << vow << "\'" << ") => " << res << '\n'; }; int main(int argc, char *argv[]) { size_t num{14266330}; cin >> num; char vow{'e'}; cin >> vow; Delete(num, vow); random_device rd; mt19937 re(rd()); uniform_int_distribution uid_n(0,10000000000), uid_v(0,4); for(int i=0; i<10; ++i) { Delete(uid_n(re), "aeiou"[uid_v(re)]); } }

[Challenge] Delete Impenitent Digit.cpp