/* Created for this code golf challenge: https://codegolf.stackexchange.com/questions/168150 Which Go rank is higher? Players of the traditional board game Go measure their skill in a system of ranks: Players new to the game are ranked 30th kyū (written 30k) and progress counting down to 1st kyū (written 1k). These are considered the student ranks. A player may promote from 1st kyū to 1st dan rank (written 1d), and then progress counting up to 7th dan rank (written 7d). These are the master ranks. Exceptionally skilled players past 7d may promote to the 1st professional dan rank 1p, and progress counting up to 9th professional dan rank (written 9p). This is the highest rank. In short: ranks are ordered 30k < 29k < ··· < 1k < 1d < 2d < ··· < 7d < 1p < 2p < ··· < 9p. Task Given two strings among {30k, …, 1k, 1d, …, 7d, 1p, …, 9p} as input, output the higher rank of the two. (If they are equal, simply output either input.) (As usual, I/O is flexible — your answer may be a function or a full program, reading input in any reasonable fashion and producing output in any reasonable fashion.) This is code-golf: the objective is to minimize your code's byte count. Test cases (Format: input1 input2 output.) 29k 9k 9k 21k 27k 21k 6d 1p 1p 5d 17k 5d 1k 1d 1d 1d 1d 1d 1d 2d 2d 9p 1d 9p 2d 30k 2d 1p 1k 1p 1d 1p 1p 1p 2d 1p 7p 8p 8p 30k 30k 30k */ // Data class for the default test cases. The first & // second strings of input and the expected result. data class Test(val first: String, val second: String, val expected: String) // Expanded version of the challenge function. fun process(first: String, second: String) = { // Lambda to make sure we have a 3 character string. val expand = {string: String -> if (string.length == 2) "0$string" else string } // expand // Convert the arguments into 3 character strings. // Save the result of the string comparision. val digit = expand(first) val number = expand(second) val result = when (digit[2]) { // When the rank of the first string is kyū, // if the second is also, the higher is the // lower number. Otherwise, it is the second // one. 'k' -> if (number[2] == 'k') if (digit < number) first else second else second // When the rank of the first string is dan, // if the second is also, the higher is the // highest number. Otherwise, if the second // one is kyū, the first is higher, otherwise, // the second is higher. 'd' -> if (number[2] == 'd') if (digit < number) second else first else if (number[2] == 'k') first else second // When the rank of the first string is // professional dan, if the second is also, // the higher is the highest number. Otherwise, // it is the first one. else -> if (number[2] == 'p') if (digit < number) second else first else first } // when result }() // Test driver for the challenge. fun main(args: Array) { val p = // 256 bytes {f:String,s:String->{val e={s:String->if(s.length==2)"0$s" else s} val d=e(f) val n=e(s) val r=when(d[2]){'k'->if(n[2]=='k')if(dif(n[2]=='d')if(dif(n[2]=='p')if(d

go cg