/* *************** Usage Example **************** The program requires 2 (two) inputs, the first one is the count of numbers to be calculated. The second is the list of numbers (integers) separated by space, so in SoloLearn Code Playground for example: 6 9 7 5 10 6 5 // <- Note the spaces NOTE: Negative numbers are allowed in the list. © 2017 SoloLearn Community *************** Challenge Info **************** https://www.sololearn.com/Discuss/853810/?ref=app Challenge::Divide The six numbers to 2 equal groups . Given a 6 numbers Check if you can divide them to 2 groups such that each group contains exactly 3 numbers and the sum of the 2 groups are equal ? if the you could do so : Print "YES" . print "NO" otherwise. sample input : 1 2 3 2 2 2 sample output: YES // you can divide them as : (1+2+3) & ( 2+2+2) */ #include const int NUMBERS {6}; int main() { int nums {NUMBERS}; std::cout << "How many numbers to work with: "; std::cin >> nums; if(!std::cin.good() || nums < 2) { std::cout << "\nInvalid input!"; return 0; } std::cout << nums << std::endl; int ar[nums]; int badInput {0}; for(int i = 0; i < nums; i++) { std::cout << "\nNumber #" << i + 1; std::cin >> ar[i]; if(!std::cin.good()) { badInput = i + 1; break; } std::cout << " " << ar[i]; } if(badInput) { std::cout << " Invalid input #" << badInput; return 0; } int sum1 {0}, sum2 {0}, top {nums - 1}; int limit {nums & 1 ? nums / 2 + 1 : nums / 2}; for(int i = 0; i < limit; i++) { sum1 += ar[i]; sum2 += ar[top - i]; } std::cout << "\n\n" << (sum1 == sum2 ? "Yes" : "No") << " the numbers " << (sum1 == sum2 ? "can" : "cannot") << " be summarized equally."; std::cout << std::endl; return 0; }

Grouped sum of array elements