/* This program convert input string with number on the some base to number with another base. Input string should be "XXXXX.A.B" where XXXXX - your request number on the original base A, and B is base for output. 2 - binary ... 8 - octal 9 - nine base system 1 - decimal A - 11th base ... F - hexadecimal Examples: 1) for enter 101010.2.0 (originally binary base number) You will get result: "Output 10-base number is: 42". 2) for enter 12467.8.F (originally octal base number) You will get result: "Output 16-base number is: 1537". 3) for enter F00F.F.1 You will get result: "Output 16-base number is: 61455". Good luck! */ #include #include #include using namespace std; int get_new_num(long long &k, int &p, int num_out[], int bout) { long long rase=1; int c=0; for (int i=1;i<=p;i++) rase*=bout; if (p>=1) { if ( (k>=rase) && (k>str; //Part of program for interpretation input base length=strlen(str)-4; int z=(int)(str[length+1]); if (65<=z&&z<=70) {binp=z-54;} if (50<=z&&z<=57) {binp=z-48;} if (z==49) {binp=10;} //Repeating for you input cout<<"You enter a "<=0;i--) { rase=1; for(int j=i;j<(length-1);j++) {rase*=binp;} num_in+=(str[i]-'0')*rase; } } else {//For usage of symbolic base rase=0; z=0; for(int i=(length-1);i>=0;i--) { rase=1; for(int j=i;j<(length-1);j++) {rase*=binp;} z=(int)(str[i]); if (str[length]=='0') {num_in+=0; continue;} if (65<=z&&z<=70) {num_in+=(z-55)*rase;} if (48<=z&&z<=57) {num_in+=(z-48)*rase;} } } //Calculation output digits and initialiaztion output array digit_out=log(num_in)/log(bout); int num_out[digit_out]; for(int x=digit_out;x>=0;x--) {num_out[x]=0;} //Calling decimal to binary thru hex converter k=num_in; p=digit_out; get_new_num(k, p, num_out, bout); //Output result cout<<"Your output "<=0;x--) { if(num_out[x]<=9) cout<9) cout<<(char)(num_out[x]+'A'-10); } }

From base (bin thru hex) to base (bin thru hex) converter