Security

input=input().replace("x","") if "G$T" in input or "T$G" in input: print("ALARM") else: print("quiet")

Say you input something like xxxxTxx$xGxx here T stands for theif $ stands for money G stands for guard and x is free space Can you say if the money is safe or not? The money will only be safe if there is a Guard between theif and the money. So if the money is not safe then an alarm should be run. But the problem is x value which is vacant floor space between them do they count? No. So we should replace those x by null value.

I have explained replace in code coach explained easy part in this way: replace is for returning the copy of the string where the occurance of one substring is replaced by another substring in simple English take a phrase and convert it into something else. Example me="I like me " x=me.replace("me","chocolate") print(x) You would get I like chocolate as output.

So here we take the input first and then replace x by null value like input().replace("x","") So the remaining part contains only G,$ andT that is guard money and theif only now if their is money between theif and guard theif can access money so the problem is with these two alignment G$T and T$G we have to sort that out by if else here

if else is used to make decision if something is true if is executed if not then else is executed

if "G$T" in input or "T$G" in input: print("ALARM")

It means if it is aligned like G$T and T$G there is no guard between money and theif theif can steal the money So the output would be AlARM again if not meaning there is a guard between money and theif money is safe output would be quiet that there would be no alarm which is refered by :

else: print("quiet")

Password Validation

number = 0 special = 0 password = input() specialcharacter = "!@#$%&*" allthenumbers = "0123456789" for a in password: if a in allthenumbers: number = number+1 elif a in specialcharacter: special = special+1 if len(password) >= 7 and number >= 2 and special >= 2: print("Strong") else: print("Weak")

Let's see the problem first. We have to make sure that the password we input have at least two numbers at least two special characters like !@#$%& and length of the password should exceed 7. Now it's code explaination time! Firstly by

number=0 special=0

I considered there is no special characters or numbers till now. Then I take the input by

password=input()

. Then by

specialcharacter = "!@#$%&*" allthenumbers = "0123456789"

I specified what the special characters and the numbers are in string. Now

for a in password: if a in allthenumbers: number = number+1 elif a in specialcharacter: special = special+1

I explained for loop and if elif statements before. for a in password woud check match the elements inside password and then inside the allnumbers and specialcharacter string. number=number+1 could also be replaced by number+=1 but I wrote that to make you understand what it does is it takes the current value of number and add one and then update it to the next value and the final value of number would be the number of numbers that match with the password. Same for specialcharacter.

if len(password) >= 7 and number >= 2 and special >= 2: print("Strong")

Here len() means length that is it would count the total characters used inside the password which should be at least 7. number of number should be at lest 2 and same for special. Here special means total number of special characters. So if length of password be more or equal to 7 number of numbers be more or equal to 2 and number of special characters which is denoted by special is more or equal to 2 Then the password is strong which would be printed.And if that don't happen which is specified by else in this line:

else: print("weak")

So then the password is weak which would be printed. Way too simple.

     Driving license  
     
     
         
         myname = input()
         
numberofagent = int(input())

otherpeople = input().split()

otherpeople.append(myname)

weall = sorted(otherpeople)

position = weall.index(myname)

print(20*(position//numberofagent)+20)
        
         
      
     By  myname = input()
         
numberofagent = int(input())

otherpeople = input().split()
      
      you need to input your name the number of agents and the other
       people's name. I am going to explain how this code works by setting
        example.
      
      So say myname = Mehnaz[= sign means Mehnaz is replacing 
      
      myname]
      number of agents is 2
      
      other people are Sofija Toto Barthika.
      
  So input() has taken input from user. 
  
  So what split() does? Split is used to split a string into a 
  
  list where each word is an item. 
  
  Look down here:
  
  
   splitwork=input()
x=splitwork.split()
print(x)  
   
   Here if we input Barthika Sofija Toto
   
   Output would be ['Barthika', 'Sofija' 'Toto']
  
   
    
that's what otherpeople = input().split()  does
      
      But they are not only here for driving licence! Me Mehnaz has to
      
      be there too. That's why I have to used append in
      
        otherpeople.append(myname)  Append used to 
      
      add a certain item in the list.
      
      
          If the input be like
          
          otherpeople=['Barthika','Sofija','Toto']
          
          otherpeople.append("Mehnaz")
           
    Output would be ['Barthika','Sofija','Toto','Mehnaz']
      
      But the checking would happen in alphabetical order. So we have to
      
      arrange the names alphabetically which is done by sorted() function.
      
 If the input be like 
              
              arrange=['Barthika','Sofija','Toto','Mehnaz']
          weall=sorted(arrange)
          print(weall)
              Output would be ['Barthika','Mehnaz','Sofija','Toto'] 
              which is in alphabetical order
            
 
      So now we need to know the position of my name
      in the arranged list. So we would use index what I did in this line
      
    position = weall.index(myname)
    
      If the input be like
       
      weall = ['Barthika','Mehnaz','Sofija','Toto']
  position = weall.index("Mehnaz")
      print(position) 
       
      
     The output would be 1 which is the position of myname. It has to
     be remembered counting starts from 0. So position is 1 refers to the
     fact that there are 1 people in front of me. Now let's explain
     this part
     
     print(20*(position//numberofagent)+20) 
      So we have to divide the number of people in front of us and 
      and divide that  by the numberofagent available. Then comes the 
      fact that each of them requires 20 minutes. Now the question is
      how much time I need to get my license. So I have to add 20 with the 
      original value and print it. 
      Look at my example. My position was 1. And there were 2 agents.So
      
      1//2 is like 2|1|0 so quotient is 0, 0*20=0 and 0+20=20
                     0
                     _ 
                     1
      
      So I need 20 mins to get my license. Well that's kind of 
      obvious there is two agent and ine will give Barthika 
      license and another will give me!!!

Code Coach Explained [ Hard ]