Q&A Discussions
Why does main have void return type, even though there are executable statements within? Is it due to the lack of the 'return'?
0 Votes
4 Answers
What is the output of this code?
int x = 65, *p = &x;
void *q= p;
char *r = q;
printf("%c", *r);
0 Votes
3 Answers
what's the difference between the int main() and void main() ? what is the best for use ?
0 Votes
3 Answers
Why we are not using void main for declaring a function? Instead we are using such as int?
0 Votes
3 Answers
Can we declare local variables in static function if no then how can we use them in static void main?
1 Vote
2 Answers
What is -public , static , void , main, in java language?? I MEAN WHAT ARE THEIR MEANINGS
1 Vote
2 Answers
void main( )
{ randomize( );int arr[ ]={4,2,1,0},n; int r= random(2)+3; for(int j=1;j<4;j++) { n=random(j); cout<<arr[n]+r<<"@";
0 Votes
1 Answer
what is the output of this code?
template<class t>
void f(t){
static int I=0;
cout<<I++;
}
int main (){
f(1);
f(1.0);
f(1);
}
2 Votes
5 Answers
public class Program {
public static void main(String[] args) {
int[ ][ ] sample = { {1, 2, 3}, {4, 5, 6} };
2 Votes
5 Answers
public class Program {
public static void main(String[] args) {
for(int x=2; x< 10; x=x*x) {
System.out.
0 Votes
2 Answers
[solved] Why this error?
3 Votes
2 Answers
C++ challenges
1 Vote
1 AnswerWhich header file to include instead of conio to use getch ,clrscr functions and declare void main instead of int main?
3 Votes
2 Answers
#include<stdio.h>
void main()
{
int i=2, j=3;
printf("%d\n",func(i,j));}
int func(int a,int b)
{
a=a-5;
b++; return(!a+- -b);}
-4 Votes
2 Answers
may anybody tell me what is the output of this function and how?? does the type of function(void) affect on the output?
0 Votes
1 Answer
What is the use of this statement "public static void main"? Is it important to use this statement in Java?
0 Votes
2 Answers
What is the output of this code? class Temp { public int num = 2; public Temp() { num++;} ~Temp() { num++; } } static void
1 Vote
3 Answers
Please Am stuck again........... Java says when void is used in a method it doesnt return any value.......
-1 Vote
2 Answers
Plz ,i need help .This void does not work well whether it is present or not. Outputs are not
0 Votes
1 Answer
Why is: public class MyClass { public static void main(String[] args ) { int x = 5; x &= 3; System.out.println(x); } } = 1??
0 Votes
3 Answers
Pblic class program {
Public static void main .string[ ] args ){
for( x=1 ; x<=100 ; x++ ){
if( x%3=0 && x%4=0)
3 Votes
3 Answers
Operations in Java
2 Votes
1 Answer
Which one is best way or easy to process for get text on button click (public void onClick /.setOnClickListner)??
1 Vote
1 Answer
in c++ program on internet Can we write
void main() instead of
Int main() and what changes we should made on it
1 Vote
4 Answers
Sir In (java) calling method, how can i determine if i am using a STATIC or VOID as a returnType? thank you,,
0 Votes
5 Answers
void means 'no return value' then is that different with a method 'println()' ?? I don't understand the difference between return value and println()...!
1 Vote
6 Answers
public class comparestrings{
public static void main (String[] args) {
String style = "Bold";
String style2 = "B
-1 Vote
1 Answer
what's the mistake in it
0 Votes
6 Answers
What you think about this?? Is it run successfully or not??if yes or no then why??lets clear basics😊😊
11 Votes
16 Answers
Will it throw error or crash if we use the void returning method in a assignment statement?
0 Votes
1 Answer
I made a function in dervied ninjA class void h() ..why i can access it my (*e1).h();...*e1 is point er of base class
1 Vote
3 Answers
public class MyClass {
public static void main(String[ ] args) {
try {
int a[ ] = new int[2];// wha
1 Vote
2 Answers
Fundamental Question on C
2 Votes
4 Answers
Explain answer plz?
1 Vote
2 Answers
Hi guys,i have a qus,what do the start do(obj.start())?
I will be grateful if you help me
class Loader extends Thread {
public void run() {
System.out.println("Hello");
}
}
class MyClass {
public static void main(String[ ] args) {
Loader obj = new Loader();
obj.start();
}
}
0 Votes
4 Answers
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