Why is a[1]=1?

Question

In the following code why is a[1]=1?:
int x=0;
int a[]={3,4};
a[x]=++×;
cout<<a[1];

Shouldn't a[1] be 4?

Answer 1

++x is a pre-increment. That is done before the statement is executed. Therefore you are setting a[1] to 1.

Answer 2

int x=0; ++x=1 so a[x]=a[0] becomes a[1] since ++x=1. ++x is pre-increment, hence the value is increased before we solve the expression.

Answer 3

3

Answer 4

yes me too I can not understand

Answer 5

++ has bigger priority from = and [] , so x=1 and you did a [1]=1

Answer 6

=1