anyone expalain me how this c++ program works?

Question

PROGRAM:

#include <iostream>
using namespace std;

void func1 (int x[]){
x[0]=0;
}
void func2(int y){
y=0;
}

int main(){
int x[]={7}, y=8;
func1(x);
func2 (y);
cout << x[0] << y;
return 0;
}

OUTPUT:
08

Answer 1

Arrays are passed by reference (address), while variables are passed by value to functions. We can see that func1 which receives an array as a parameter is able to change the original value of the array, while func2 does not.

Answer 2

Arrays can actually be modified by a function calls because it's address is passed by reference to the function that calls them while the same cannot be said for variable which is passed as a copy except you explicitly pass it with the reference operator.

Answer 3

Music. Replay

Answer 4

the array above can be altered by the fun1 but the variable can't