Can you explain how this while loop works?

Question

print("enter the value of n")
n=int(input())
sum=0
avg=0.0
i=1
while i<10:
sum=sum+i
i=i+1

print("sum is:",sum)
avg=sum/n
print("Average is:",avg)

NOTE: It's a python code for those who don't have an idea.

Answer 1

From line 5 we know 1 is assigned to variable "i", and from line 3, 0 is assigned to variable "sum".
The while loop says:
When i is less than 10, new sum is equal to old sum + i.
In order words, sum is equal to current value of sum plus i.
To visualize, it is "sum = 0 + 1", thus sum become 1.
After the calculation the program execute "i = i + 1". It works in the same way as explained above.
After that it will jump back to while i < 10, and check if i < 10 is true or not.
If it is true, the while loop will run again.
It will keep repeating until i = 9 + 1, and jump back to while i < 10.
In the next while loop, i < 10 become 10 < 10.
Since 10 < 10 is not true, the while loop will not be executed and jump to the line "print("sum is:", sum)" and continue.

Answer 2

The while loop in this code accumulates the sum of the first 9 natural numbers. It begins by initializing 'i' to 1 and runs while 'i' is less than 10. In each iteration, 'i' is added to 'sum,' incrementing 'i' by 1 to avoid an infinite loop. Once 'i' reaches 10, the loop ends. This loop ensures the sum of the first 9 natural numbers is calculated and stored in 'sum.'

Answer 3

Bhagya Buch ,

Why do you ask the user for a number to divide by when you hard code a sum of 9 numbers that requires dividing by 9 to get an average? Just hard code the division by 9 as well.

Either that, or use the input to determine how many numbers are summed as well as the divisor.