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Creating a self-numbering ranking list

Can someone offer a solution to this problem? Say I a ranked list: 5. Pineapple 4. Peach 3. Kiwi 2. Apple 1. Banana I then add a new entry to the ranking: 5. Pineapple 4. Peach #. Plum <--new text 3, Kiwi 2. Apple 1. Banana Can I set up the list to automatically reorder as follows? 6. Pineapple 5. Peach 4. Plum 3, Kiwi 2. Apple 1. Banana Thanks!

26th Dec 2022, 6:30 PM
Savager
3 Answers
+ 1
use can use the Slicing indexing in Python to split and append a new element and then join it to create a new list with the new element having a certain index. Here is the code and I want you to learn from it not just expect answers from the community. https://www.sololearn.com/compiler-playground/cSka5pKO8H6X
26th Dec 2022, 7:18 PM
Vanessa Nilsson
0
Savager you should try list.insert() or you can use OOP for more advanced list operations: https://realpython.com/inherit-JUMP_LINK__&&__python__&&__JUMP_LINK-list/
28th Dec 2022, 2:58 PM
Bob_Li
Bob_Li - avatar
0
#Savager copy-paste this: #class inherit from list class MyList(list): def __init__(self, li): super().__init__(v for v in li) #custom __str__method def __str__(self): s = "" for i, v in enumerate(self): s+=f'{len(self)-i}. {v}\n' return s #custom insert method def insert(self, i, v): super().insert(len(self)-i, v) ## TEST ## fruits = MyList(['Pineapple', 'Peach']) #custom __str__method print(fruits) #built-in list methods fruits.append('Kiwi') fruits.extend(['Apple', 'Banana']) print(fruits) #custom insert method fruits.insert(3, 'Plum') print(fruits)
29th Dec 2022, 3:41 AM
Bob_Li
Bob_Li - avatar