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¿¿Why the output in JavaScript is []??

const ovejas = [ { name: 'Noa', color: 'azul' }, { name: 'Euge', color: 'rojo' }, { name: 'Navidad', color: 'rojo' }, { name: 'Ki Na Ma', color: 'rojo'}, { name: 'AAAAAaaaaa', color: 'rojo' }, { name: 'Nnnnnnnn', color: 'rojo'} ] function contador(n) { return n.filter(n => n.color === 'rojo') .filter(n => `${n.name}`.includes('n')) .filter(n => `${n.name}`.includes('N')) .filter(n => `${n.name}`.includes('a')) .filter(n => `${n.name}`.includes('A')) } console.log(contador(ovejas))

5th Sep 2022, 10:20 PM
Josué Varela
Josué Varela - avatar
1 Answer
+ 2
It's not getting a a match and returning an empty array. The filter is looking for name with ALL 4 letters in it. this matches any of the letter for example. const ovejas = [ { name: 'Noa', color: 'azul' }, { name: 'Euge', color: 'rojo' }, { name: 'Navidad', color: 'rojo' }, { name: 'Ki Na Ma', color: 'rojo'}, { name: 'AAAAAaaaaa', color: 'rojo' }, { name: 'Nnnnnnnn', color: 'rojo'} ] function contador(n) { return n.filter(n => (n.color === 'rojo' & (n.name.includes("n") | n.name.includes("N") | n.name.includes("a")) | n.name.includes("A"))) } console.log(contador(ovejas))
5th Sep 2022, 11:41 PM
morl
morl - avatar