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1st May 2022, 4:04 PM
proGAMBLER
proGAMBLER - avatar
5 Answers
+ 8
When a string literal (even an empty one) is used in an evaluation e.g. an `if` conditional; the memory address of the literal is used instead. Try to print the address and you'll see it's non zero even though it's an empty string literal. printf( "%p\n", "" ); And as you probably know already, a non zero value is considered truthy, and thus the `if` block is chosen. On the contrary, if you try to get the first char off the empty string literal; you'll get a zero ('\0' when being represented as a char) because the literal was empty. And therefore you'll end up entering the `else` block because a zero is considered falsy. if( *"" ) // evaluates to false Hope I get it right ...
1st May 2022, 5:31 PM
Ipang
+ 1
Ipang you mean if we use * then it will use value inside double quotation and writing without * will use address of given string ...* will point out value of empty string am I right ?
2nd May 2022, 7:29 AM
proGAMBLER
proGAMBLER - avatar
+ 1
- A snippet showing example of evaluation involving `cout` is still closely related to your recent question https://www.sololearn.com/Discuss/3026360/?ref=app. If you read the link in Jayakrishna's answer in that post you'll understand why it is so if( !cout << true ) // recommend to use parentheses if( !( cout << true ) ) - As for the evaluation of '¥0' It's not a valid char literal because it contains more than one character. You should be getting a warning about this I suppose. - About the use of * (indirection or dereference), I suppose a web search on pointer and pointer arithmetic might provide you a better explanation than any I could ever do : )
2nd May 2022, 11:47 AM
Ipang
0
// Online C++ compiler to run C++ program online #include <iostream> using namespace std ; int main() { if(!cout<<true){ cout <<"True "; } else {cout <<"False";} return 0; } In this code, condition in if statement is not executing why?
2nd May 2022, 6:46 AM
proGAMBLER
proGAMBLER - avatar
0
#include <iostream> using namespace std ; int main() { if('¥0'){ cout <<"True "; } else {cout <<"False";} return 0; } This code is also executing True condition ..
2nd May 2022, 6:49 AM
proGAMBLER
proGAMBLER - avatar