Why I'm facing this error in python, can someone explain please

Question

Let's say we have this list
m = [[1, 2, 3], [4, 5, 6]]
and I want to check if the number 2 is inside this list so I wrote the following code:
print( 2 in m) the output is False .However when I wrote:
print(2 in m[0]) the output is True.
So why the second code is working while the first is not

Answer 1

Ahmad Anbar ,

we have to use an iteration with a for loop over all sub-lists (elements) in list m:

m = [[1, 2, 3], [4, 5, 6]]
found = False
for lst in m:
if 2 in lst:
found = True
print(found)

Answer 2

FF9900 ravilnicki Yones Mussa Lothar
Thanks guys 👍
I think I got it now

Answer 3

It because you have a nested list. You are accessing the nested list when you check for 2 but when you do m[0] is checking the list inside the list

Answer 4

#outputs:
[1, 2, 3]
[4, 5, 6]
#and
1
2
3

Sorry still didn't get it