Why is there an error on "gets" in this code of a string while compiling?

Question

#include <stdio.h>
int main() {
char s[30];
int x,c=0;
printf("Enter the string to find length");
gets(s);
for(x=0;s[x]!='\0';x++)
{
if(s[x]!=' ')
{
c++;
}
}
printf("\n %d",c);
return 0;
}

Answer 1

gets is depreciated. use fgets

Answer 2

In my laptop using vscode with gcc engine compiler this code works fine. When a function is deprecated it still may work and sometimes compiler delivers a warning message. In C++ gets was excluded because it is dangerous. "gets" accept any char array of string and it can cause buffer to overflow by a billion character input. I believe this used to be a source of crashs in softwares. Anyway fgets is highly recommended because you can limit the number of characters passed by an input. Last, your code is a bit smart (I prefer straight simple code), but your code is totally fine in my humble view.

Answer 3

I published your code here: https://www.sololearn.com/post/1477883/?ref=app
As you can see, it compiles fine.