Dejavuu

Question

Anyone with the idea of how to solve the Dejavuu problem? Kindly assist

Answer 1

rupali
Your code checks the characters are serial, here one of your code lines
if(a[i] == a[i+1]) // this line checks just two characters in order.
I mean, if you enter this string "gkhgkh" it says "Unique" but it must be "Deja Vu".

If I'm wrong, said sth incorrect, I'm really sorry. But I told the reason.

Answer 2

Michael Owen Kindly share your attempt, so we can help you :)

Answer 3

#include <iostream>
#include <string.h>
using namespace std;

int main() {
char a[20];
cin>>a;
int k;
if (k=strlen(a)){

if(a[k]==a[k]){
cout<<"Deja Vu"<<endl;
}
else{
cout<<"Unique";
}

}

return 0;
}

Answer 4

Michael Owen
https://code.sololearn.com/cuazv2xalIEG/?ref=app

Answer 5

Thank you

Answer 6

rupali
Your code always prints "Unique". Cause if the characters in the given string are serial. Check your code. Happy coding!

Answer 7

rupali
Okay, I see. Thanks for understanding. Happy coding!

Answer 8

Michael Owen
Your code always prints "Deja Vu". Cause you compare the same element with itself. Check your code. Happy coding!

Answer 9

mesarthim it's running fine...And passing all the test cases...Will you please describe the issue a little bit more? :|

Answer 10

mesarthim
It's all right, to get correct answer according to your input we can use nesting of loops, but there is no need of nesting as the challenge says.