How did u solve the Coffee Time, last task on c# course?

Question

Here is my code. I think i cheated a little. But it worked.
static void Main(string[] args)
{
double discount = Convert.ToInt32(Console.ReadLine());
Dictionary<string, double> coffee = new Dictionary<string, double>();
coffee.Add("Americano", 50);
coffee.Add("Latte", 70);
coffee.Add("Flat White", 60);
coffee.Add("Espresso", 60);
coffee.Add("Cappuccino", 80);
coffee.Add("Mocha", 90);
//your code goes her
foreach(KeyValuePair<string, double> kvp in coffee)
{
double newPrice = (100-discount)/100*kvp.Value;
Console.WriteLine("{0}: {1}", kvp.Key, Math.Ceiling(newPrice) );

Answer 1

(1-discount*0.01) try like this to keep it in double

Answer 2

You can try this solution‘s form:
coffee[sc] -= discount * coffee[sc] / 100;

Answer 3

instead of using ceil function... do it manually and try

Answer 4

I tried without ceiling function, but it gave me every value as 0. And all doubles were integers but didnt print as wanted.

Answer 5

foreach(KeyValuePair<string, int> entry in coffee)
{
Console.WriteLine(entry.Key +": "+(entry.Value-entry.Value*discount/100));
}

Answer 6

Jackie looks good except for the <string, int> should be a <string, double> (maybe they changed it since then)