Please I do not have any idea how to solve this problem

Question

https://www.sololearn.com/coach/4?ref=app
I am a beginner.,Thank you.

Answer 1

It simple, you have two houses are giving out dollar bills, and suppose the number of houses that you visited is (n). Therefore the porcentage of one random item pulled from your bag is a dollar bill it 2/n*100=> 200/n ....✌

Answer 2

Big up👐
scanf("%d", &h);

int a=200/h;
if(200%h) a++;
printf("%d",a);

Answer 3

math import ceil
houses = int(input());
prc= ceil((2 * 100) / houses);
printf(prc);

Answer 4

#include <stdio.h>

int main() {
int h, a;
scanf("%d", &h);
//h=number of houses
//a= Probability of getting doller bills
//your code goes here
a=100-(h-2)*100/h;
printf ("%d",a);
return 0;
}
// I think it will be helpful to you 🙂

Answer 5

show my page

Answer 6

The <applet> tag in HTML was used to embed Java applets into any HTML document. The <applet>tag was deprecated in HTML 4.01, and it’s support has been completely discontinued starting from HTML 5. Alternatives available in HTML 5

Answer 7

Try this
houses = int(input())

import math
percent = math.ceil( 2 * 100 / houses )
print ( percent )

Answer 8

Simple arithmetic problem. You have to learn first how If else Works.

Answer 9

Yes for sure I gonna use the if else statement but I don't have any idea about the conditions
Thank you busydev.

Answer 10

But please why exactly 200

Answer 11

Or you can use ciel() easily but it stell work anyway

Answer 12

Ciel()??is this a function?

Answer 13

Okay I get you now.
Thanks

Answer 14

You're welcome

Answer 15

If (200/h)=if(200/h!=0)??

Answer 16

I mean ceil() in math header file...

Answer 17

Oui les deux expression sont equivalent

Answer 18

Ah d'accord mais est ce qu'il est nécessaire d'utiliser la fonction ciel.
Pardon mais j'ai aucune idée à propos de cette fonction

Answer 19

Non,non ce n'est pas nécessaire

Answer 20

Alright. Thank so much for your help