What is the output of this code???

Question

https://www.sololearn.com/post/262217/?ref=app

Answer 1

Well, let's make this "Why is the output of this code?".

The C standard actually clearly defines this case (yes, once in a while, something is not Undefined Behaviour in C). When an attempt is made to read an inactive member of a union, the appropriate part of the object representation of the value is reinterpreted as the type of the accessed member. This process is known as "type-punning" and only a thing in C, but not C++.

So, since "ch" is already conveniently the same size as 'i', it is reinterpreted as short int. The SoloLearn environment is a little-endian one, meaning the most significant byte is actually on the right, as opposed to a big-endian system.

"ch" is stored in binary as
00000011 and 00000010,
but since the right byte is the most significant one, the resulting combined integer would look like this in binary represantation (from left to right)

0000001000000011

which in the end equals 515 as the last number in the output.

Answer 2

You can also check on Sololearn Playground.

Answer 3

Waaoo i got it and thanku veryyyy much