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Sum with arbitrary amount of brackets. Why does it work?!?!?

I’ve found this in js tutorial and I really can’t understand how it works. function sum (a) { let currentSum = 0; function func (b) { currentSum += b; return func; } func[Symbol.toPrimitive] = function () { return currentSum; } return func; } console.log(sum(5)(10)) // 15 console.log(sum(5)(10)(15)) // 30 I understand that here we use closure. What I really can’t understand why we need to transform function to primitive? Please explain me. I really start to feel panic bec I can’t understand that thing

2nd Oct 2019, 4:20 AM
max
max - avatar
3 Answers
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max In normal circumstances, we cannot perform add or multiply operations on object or function. Eg. 2+obj1 + obj2 or 3*fn1+fn2 (errors) However string can be auto type convert to number by default eg. +str1 Number also can be auto type convert to string when, eg. "a" + 100 For function and object, we can perform type conversion too, by using Symbol.toPrimitive. Symbol.toPrimitive allows object to be acted like primitive var, it also controls the output of the primitive value. More information check out the code, I have added more examples to show how does Symbol.toPrimitive alter the object/function in type conversion. https://code.sololearn.com/W0iY3PK3mLBP/?ref=app Since you understand closure, I would not explain the closure part of your code here.
3rd Oct 2019, 2:08 PM
Calviղ
Calviղ - avatar
+ 1
still dont understand why do we need to transform the function? I know how symbol.toprimitive works and i know that functions are objects so we if we want to do some calc with them we need to transform them. But I cant figure out why should we transform the func in this ex??
4th Oct 2019, 3:35 AM
max
max - avatar
0
If you try to remove func[Symbol.toPrimitive] = function () { return currentSum; } you would get unprotected function code output on console.log due to function code cannot transform to primitive value. This code func[Symbol.toPrimitive] = function () { return currentSum; } enables console.log to output a primitive value in the final output value instead of function code, when it was not called by function (n). This is a way how closure protects its own function codes being exploited to external, while letting function implementation set as public Study this example: https://code.sololearn.com/WcieGEM2PV9G/?ref=app
4th Oct 2019, 5:21 AM
Calviղ
Calviղ - avatar