i=5; what is the output of i=(++i/i++);

Question

explain

Answer 1

Answer: i=1

The code in words verses the code:

1) insert 5 into i --- i=5
2) insert into i the result of --- i=
3) prefix i --- ++i
4) which means it increases the value of i by one and then uses it.

so now i=6 and the code is:

i=(6/i++)

5) postfix i --- i++
6) which means it first uses i in the code and then increases it by 1 (before it starts to run on the code again).

so now the code is: i=(6/6)

and i=7

7) insert into i (6/6), which equals 1.

So i=1.

Answer 2

but in my compiler its output is 2

Answer 3

I wrote the code here: https://code.sololearn.com/cT2frmvJ36FM/?ref=app