Switch case Python, no corre que falta?

Question

opcion = int(input("Menu \n -----------\n \t"+"1. Cuadrado \n \t2. Triangulo \n \t3. Circulo \n \t4. Romboide \n \t5. Rombo \n \t6. Trapecio \n \t "+"POR FAVOR INGRESE LA OPCION QUE DESEE:"));

if  ( opcion == 1):

X= float(input('ingrese lado '))

A= X**2

print (A)

 # cuadrado

elif (opcion == 2):

b= float(input('ingrese base '))

h = float(input('ingrese Altura '))

Area= b*h/2

print (Area)

 # triangulo

elif (opcion == 3):

π = 3.14

R = float(input('ingrese Radio '))

Are = π*R**2

print (Are)

 # circulo

elif (opcion == 4):

base1= float(input('ingrese base '))

haltura = float(input('ingrese Altura '))

areaaa = base1*haltura

print (areaaa)

 #romboide

elif (opcion == 5):

D = float(input('ingrese Diagonal Mayor '))

d = float(input('ingrese Diagonal Menor '))

AREA= D*d/2

print (AREA)

 #rombo

elif (opcion == 6):

X = float(input('ingrese base mayor '))

Y = float(input('ingrese base menor '))

Z = float(input('ingrese altura '))

A= (X+Y)*Z/2

print (A)

 #trapecio

e

Answer 1

J'espère que tue comprends mauvais francais. Il n'y a pas de switch statement, mais on peut utiliser une dict (there is no switch statement, but you can use a dict instead):

def cuadrado():
X = float(input('ingrese lado'))
A = X**2
print(A)

def triangulo():
b = float(input('ingrese base '))
h = float(input('ingrese Altura '))
Area= b*h/2

# etc.

options = {1: 'cuadrado', 2: 'triangulo'} # etc.

c = int(input('What do you want to calculate? [1) cuadrado, 2) triangulo]')) # etc.

exec(options[c] + '()')

Answer 2

Jeisson Camilo Rincón ,

match case Python 3.10 😎

Sololearn uses Python 3.9.16 😭

https://peps.python.org/pep-0636/