can't understand what's happening in output pls help. is 0 being taken as false and not 0 as true . So as 3 is true but not not | Sololearn: Learn to code for FREE!
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can't understand what's happening in output pls help. is 0 being taken as false and not 0 as true . So as 3 is true but not not

if 0: print("yes") if not 0: print("lol") if 3: print("yes") if not 3: print("lol") output- lol yes

5th Nov 2018, 1:09 PM
partha
partha - avatar
3 Answers
+ 2
Its better understand that "if" statement want an boolean value else python have to convert it to boolean. Then, the problem, is understand as python convert types to boolean. Well: - All numeric values will be converted to true except 0 - All class objects will be converted to true except when you define custom __bool__ operator - None is always converted to false - Strings are converted to true if are not empty strings, else false
5th Nov 2018, 2:16 PM
KrOW
KrOW - avatar
+ 5
0 has always a boolean value of false every other number returns true - nums included
5th Nov 2018, 1:15 PM
Mbrustler
Mbrustler - avatar
+ 3
Mostly program languages do it like Mbrustler said. A think you are confuse because in SHELL you have 0 as exit_success and non-zero means exit_failure, in other words, it's backwards.
5th Nov 2018, 1:30 PM
Anya
Anya - avatar