(A time limit)Given the string, check if it is a palindrome.

Question

[execution time limit] 4 seconds (py3)

Here’s my code, I want to know how to make it faster,thank you very much ᕕ(ᐛ)ᕗ

def checkPalindrome(inputString):
inputString = input("Please output a string: ")
if len(inputString) < 10**5 and len(inputString) > 1 :
return (inputString == inputString[::-1])

Answer 1

def checkPalindrome(inputString):
reverseString=((inputString)[::-1])
if inputString==reverseString:
return True
else:
return False

Answer 2

that's faster😅

Answer 3

str = input()
print (True if str == str[::-1] else False)

and you can just turn it in to a function by doing
def pal(str)
print (True if str == str[::-1] else False)