+ 6

User Input in PHP

I just recently finished the PHP course, and it seems that the only way to get user input is by using HTML. Does anyone know if there's a way to get user input directly from within PHP, such as input() in Python or cin in c++? Thanks in advance!

6th Jan 2018, 11:35 PM
Faisal
Faisal - avatar
5 Answers
+ 11
You don't. PHP is used to scrape stuff out of HTML. So you create a HTML form. Then in the form element you can have: method="POST"/"GET" as an attribute. Then, <?php a=$_POST["value"]/$_GET["value"]; echo a; ?>
6th Jan 2018, 11:50 PM
πŸ‘‘ Prometheus πŸ‡ΈπŸ‡¬
πŸ‘‘ Prometheus πŸ‡ΈπŸ‡¬ - avatar
+ 7
No way, it's restricted with HTML form tag.
6th Jan 2018, 11:53 PM
Ahmad Bahbouh
Ahmad Bahbouh - avatar
+ 5
@Ahmad Nope, you can try ;)
6th Jan 2018, 11:55 PM
πŸ‘‘ Prometheus πŸ‡ΈπŸ‡¬
πŸ‘‘ Prometheus πŸ‡ΈπŸ‡¬ - avatar
+ 4
No, there isn't a way it's only working with html:(
6th Jan 2018, 11:49 PM
Michael55555
Michael55555 - avatar
+ 1
There is no other way. You have to use html to pass data (input). Never heard of php prompt or something like that. But the php part is not so bad after all... (joke, bad one i know) So the basic flow looks like this : So html form looks like that: <form action="send_to_database.php" method="post"> Then the fun with PHP starts. PHP script in steps 1. check connection: $con = mysql_connect("server address","DB_id","DB_password"); if (!$con) { die('Could not connect: ' . mysql_error()); } ------------------------------- 2. Select needed database: mysql_select_db("DB_id", $con); ------------------------------- 3. Now start transfering values: $sql="INSERT INTO table_name (some_text) VALUES $_POST[some_text]; ------------------------------- 4. Again now we check if everything is OK. If not we want to know. if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "success!"; ------------------------------- 5. Close connection: mysql_close($con) Now the closing connection part is essential for safety reasons and to avoid problem like you want to send some data from another form and connection to the former table is still open... Imagine now that address data tries to fit in personal data table - Impossible because column names are different so php will throw error after error. Nothing bad in testing phase but when site is online... And that should be it. I hope i`ve managed to clairfy this a bit.
7th Jan 2018, 3:21 PM
Karol Michalik
Karol Michalik - avatar