What is the output of the following code?

Question

v=[1,2,3]
r=[ 'g', v[:], 'a' ]
v[1]=0
print(r)

Answer 1

you could've tested it yourself on code playground...

Answer 2

@drishti r != [ 'g' , [1,0,3], 'a' ] because python code are executed top to down by interpreting the code line by line so in first instruction it assign an array
v=[1,2,3]
then it interprate and execute the 2 instruction which is r=['g', v[:] ,' a'] by which output come as
[ 'g' , [1,2,3], 'a' ] and then it execute 3rd instruction v[1]=0 by which the value of the 2 element of array v become 0
then it execute 4 instruction print (r)
which prim the value of r which is [ 'g' , [1,2,3], 'a' ] and if you now print(v) it will print v[1,0,3]

Answer 3

If you switch lines 2 and 3 you do get [ 'g' , [1,0,3], 'a' ].

Answer 4

@Gawen print(v) will print v[1,0,3] of course thats just a typo.
You have such a funny profile.
I would like to call you a: Code Gamer.
No offence of course, you made me asked myself, why i don't like to be challenged...while you seem to love it....i m still confused😂😠😨😄.....😉

Answer 5

welcome @drishti don't worry you will understand the behavior of python language very soon because it is really nice language 😊😊

Answer 6

['g', [1,2,3,], 'a']
Look it please ↑↑↑ :)

Answer 7

I am not getting why v[1] doesn't get updated while printing r

Answer 8

yesss ... thanks @David :)

Answer 9

please can you explain me why r != [ 'g' , [1,0,3], 'a' ]

Answer 10

Oh.. thanks @Gawen . Python is my first programming language so my basics are not that great as of now.
thank you so much :)

Answer 11

yes, I am loving the process.. :)