Why the code does not working ?

Question

I want to print equivalent characters of 0 to 20

why this code does not working ?

https://code.sololearn.com/c4lg1AajarFz/?ref=app

Answer 1

Your only outputing the char value of 0, 21 times. 0 doesn't have a visible character. Nor do any values up to 20. Check against an ascii table:
http://www.asciitable.com

You can try something like:
count = 97 # a
while count <= 122: # z
print (chr(count))
count = count + 1

Answer 2

Or something along this line:

print(*(chr(i) for i in range(33, 127)))

Answer 3

Just read your question again.
And the others are correct, that you don’t need the variable “a”, just cast the counter to char. However not all characters are printable, hence I believe what David is saying , any char less than 33 might not behave as expected.

Answer 4

I agree with ChaoticDawg

I would try something like:
count=0
a = 97 # a
while count <= 25: # z
print (chr(count+a))
count = count + 1
print (count) ## always add print lines near questionable code so you can visually see what is happening