Casting char in java

Question

Can anyone tell me why this doesn't work please as i thought this would cast letters from A upwards but keep getting numbers?

char str = 'A';

for(int i = 0; i<100;++i){

System.out.println((char)str+i);}

Answer 1

That's because 'str' is already a char type variable. And statements are executed from left to right. And when doing math, the result is casted automatically to the larger type (char to int - in that case).
It's executed like that:
((char) str) + i - and you get an integer result

It should be:
(char) (str + i) - gets the integer result first, and then casting it to char.

Answer 2

You could also do something simple like this:

for(char i = 'A'; i <= 'Z'; ++i) {
System.out.println(i);
}

Answer 3

Just change the last line to System.out.println((char)(str+i));}

Answer 4

It naturally comes from the mathematic.
Example:
x = 4 + 4 / 2 * 4
x = 4 + 2 * 4
x = 4 + 8
x = 12

As we know, the multiplying and the dividing comes before the addition and the subtraction. But what's in the parentheses is calculated first.
x = (4 + 4) / (2 * 4)
x = 8 / 8
x = 1

Or:
x = ((4 + 4) / 2) * 4
x = (8 / 2) * 4
x = 4 * 4
x = 16

In the programming is recomended to use parentheses, even when the calculations are obvious.
x = 5 + 3 - 2
=>
x = (5 + 3) - 2

Or:
x = 5 > 6 || 8 > 6
=>
x = (5 > 6) || (8 > 6)

Answer 5

It's because you're casting str then adding 1 to it. So, all you need to do is as @MuzzRK stated to make sure that the cast happens after the value is chnged.

Answer 6

thanks for your help guys ☺ @ boris were do i learn to use parenthisis like this properly as i havent been taught this in school and i see alot of people using this with multiple numbers and parenthisis in for() loops. thanks

Answer 7

@boris thank you thats brilliant i understand it now and if the order of operation has parenthisis do that first 😉