can any one tell how to remove this error??

Question

import java.util.*;
import java.lang.*;
class sample
{
public static void main(String args[])
{ int x,y,z;
Scanner sc=new Scanner(System.in);
System.out.print("\n\tenter 1st value:");
boolean b=sc.hasNextInt();
if(b==true)
{
x=sc.nextInt();
System.out.print("\n\tX:"+x);
}
else
{
do
{
System.out.print("\n\tinvalid value:");
System.out.print("\n\tenter 1st value:");
x=sc.nextInt();
}while(b=false);
}
Scanner sc=new Scanner(System.in);
System.out.print("\n\tenter 2nd value:");
boolean b=sc.hasNextInt();
if(b==true)
{
y=sc.nextInt();
System.out.print("\n\tY:"+y);
}
else
{
do
{
System.out.print("\n\tinvalid value:");
System.out.print("\n\tenter 1st value:");
x=sc.nextInt();
}while(b=false);
}
z=x+y;
System.out.print("\n\tRESULT:"+z);
}
}

Answer 1

change:
while (b=false);

to:
while (b == false);

OR

while (!b);

Remember = is not a comparison operator.
*Keep in mind this will become an infinite loop since b is never set back to true*

You also created 2 local variables with the same name after your first loop.
Remove the 2nd Scanner:
'Scanner sc = new Scanner (System.in);'

and

Change the name of the 2nd boolean variable 'b' OR do not create a new boolean variable.
change:
boolean b = sc.hasNextInt();
to:
b = sc.hasNextInt();
or
boolean hasNext = sc.hasNextInt();
// and modify everytime b was accessed to use this name instead

Answer 2

Ah, that would be because if the 2nd if statement:
if (b == true) is false, then y is never given a value when it is accessed with z = x + y; (2nd last piece of code).

I'm not sure what you were trying to do but to fix the error you can set y by default to be equal to 0.
change:
int x, y, z;

to:
int x, y = 0, z;

Answer 3

Maybe tell the output (error message)?

Answer 4

@Rrestoring faith tq for d answer.....but I'm also getting error like "variable y might not have been initialised"

Answer 5

@Restoring faith....tqq it worked well 😀😀