Help is needed there how do I solve?

Question

ax^2+6x+c=0

Answer 1

it's in the form of ax²+bx+c=0 which is a quadratic equation. The solution to this is given by:
x = (-b±√(b²-4ac))/2a here b=6 so...
x = (-6±√(36-4ac))/2a which can be simplified to...
x= (-3±√(9-ac))/a
Hope this answers your question =)

Answer 2

The value(s) of x what you get above after using the equation is the roots of the equation. write this equation in Fortran programming language and make it print the value(s) of x.

Answer 3

thnx

Answer 4

it says, using Fortran as language program to obtain the root of quadratic equestion "ax²+bx+c=0"

Answer 5

thanks again