IP Validation Challenge 2⃣5⃣5⃣.2⃣5⃣5⃣.2⃣5⃣5⃣.0⃣

Question

Write an algorithm that will identify valid IPv4 addresses in dot-decimal format. IPs should be considered valid if they consist of four octets, with values between 0..255 (included).

valid input:
1.2.3.4
123.45.0.86
0.0.0.0
255.255.255.255

invalid input:
hello >> not a possible ip
1.2.3 >> 3 octets
1.2.3.4.5 >> 5 octets
123.456.78.90 >> 456 is greater than 255
123.023.01.102 >> 023 and 01 are not valid
abc.def.sae.jei >> seriously?
222.-34.224.123 >> no negative numbers

Every language is welcome!

Answer 1

My try:
https://code.sololearn.com/WfgOIxKx5S72/?ref=app

Answer 2

Marking thread. Will come back to this later.

Answer 3

Java :D

https://code.sololearn.com/cJ4fEiJPm0A3/?ref=app

Answer 4

@Andrea : Edited the code accordingly!

Answer 5

my try 🐍
https://code.sololearn.com/cm2s2FaH787j/?ref=app

Answer 6

https://code.sololearn.com/ci0L14KWyu3d/?ref=app

Answer 7

My try

https://code.sololearn.com/cPsE59Zh1OOf/?ref=app

Answer 8

I'm a bit busy today, so this one is kind of crude.
https://code.sololearn.com/cIU09T5S33Cp/?ref=app

Answer 9

@Teja 012 is not valid so 4 example
123.123.012.123 is not a valid ip

Edit: good work!

Answer 10

https://code.sololearn.com/Wt3B4695IXbQ/?ref=app

Answer 11

https://code.sololearn.com/cPpz06Q8S3B0/?ref=app

Answer 12

https://code.sololearn.com/cAGmTh89Ui9Z/#cs

Answer 13

here's my link
Thx python regex lol
https://code.sololearn.com/c9u7OYp4uL88/#py

Answer 14

My solution with Python:
https://code.sololearn.com/cRRD2bOZkiSX/?ref=app

Answer 15

@Stoyan There are some issues with your otherwise good code:
- negative octets are possible
- leading zeroes are allowed in your implementation

Also, you could just output the method parameter instead of interpolating the octets together because the input obviously is valid at that stage.

Answer 16

Special approach:
Filter using language features and behaviors, not by values
Primarily by: exception, -mod behavior, recast length

https://code.sololearn.com/cd03CF9McF30/?ref=app

Answer 17

@calvin this is cheating! ahahah!

Answer 18

@amr 123.012.123.123 is not valid because 012 is not valid

Edit: nice!

Answer 19

fixed

Answer 20

did I? which one?