How can I declare an array of pointers..

Question

I want to create two arrays of same length one which can store number another which can store its pointers..

Answer 1

To create an array of pointers, the following syntax may be used:

type* array_of_pointers [size_t size];

Eg - int* arr[6];
// An array of 6 int pointers, each having a capacity to store a reference of an element, or an int array...

Answer 2

@Kinshuk Vasisht (+1)

I say, that's an array of pointers!

</declaration>

Answer 3

Thanks.. @ Kinshuk Vasisht..

Answer 4

but how will I associate that array of pointers... with my array of integer..

will this be like..

int a[6];
int *p[6];
*p[6]=&a[6];

Answer 5

@Aryan Sharma

Use a for loop, in the following way :

for(size_t i = 0; i < size; i++)
{
arr[i] = &a[i];
}

Thats it. To use, dereference in the following way :

cout << *(arr[3]) << endl;
// Print 4th element of a.

Answer 6

I think this code should resolve your query...
https://code.sololearn.com/cBf3xrkk8j0q/?ref=app