Can someone help me convert below c++ to codes into C++ function???

Question

#include <iostream>
using namespace std;

int main() {
int num1, num2;
cout<<"enter two integers"<<endl;
cin>> num1 >> num2;
int sum;
sum = num1 + num2;
cout<< num1 <<" + "<< num2 <<" = "<<sum<<endl;
int sub;
sub = num1 - num2;
cout<< num1 <<" - "<< num2 <<" = "<<sub<<endl;
int mult;
mult = num1 * num2;
cout<< num1 <<" * "<< num2 <<" = "<< mult<<endl;
int div;
div = num1 / num2;
cout<< num1 <<" / "<< num2 <<" = "<<div<<endl;
int mod;
mod = num1 % num2;
cout<< num1 <<" % "<< num2 <<" = "<< mod<<endl;
return 0;
}

Answer 1

#include <iostream>
using namespace std;

void sum(int num1, int num2) {
int sum;
sum = num1 + num2;
cout << num1 << " + " << num2 << " = " << sum << endl;
}

void sub(int num1, int num2) {
int sub;
sub = num1 - num2;
cout<< num1 <<" - "<< num2 <<" = "<<sub<<endl;
}

void mult(int num1, int num2) {
int mult;
mult = num1 * num2;
cout<< num1 <<" * "<< num2 <<" = "<< mult<<endl;
}

void dive(int num1, int num2) {
int div;
div = num1 / num2;
cout<< num1 <<" / "<< num2 <<" = "<<div<<endl;
}

void mod(int num1, int num2) {
int mod;
mod = num1 % num2;
cout<< num1 <<" % "<< num2 <<" = "<< mod<<endl;
}

int main() {
int num1, num2;
cout<<"enter two integers"<<endl;
cin>> num1 >> num2;
sum(num1,num2);
sub(num1,num2);
mult(num1,num2);
div(num1,num2);
mod(num1,num2);
return 0;
}

if you need them to return a value, then you need:
int sum (int a, int b) {
return a + b;
}

Answer 2

Yes I would like them to return value