What is the output? x=0 while x<5: x=x+2 print(x) How the answere is 6? Prblem:2 x=0 a=[ ] while x <=3: x*=2 a.append(x) print(a) How the answere is infinite loop? Explain please!
Problem 1 X= 0, in first loop x= x+2 = 2, second 2+2;= 4, and third 4+2= 6, then x>5 so while loop breaks. And x is printed. Problem 2 Your while loop is an infinite loop because perhaps you forgot to increase x, in the loop.
No, you are misunderstanding while loop with for loop perhaps or idk. It is straight x= 0+2, 2+2,4+2
Problem 1: The while loop does 3 iterations before exiting, each time adding 2 to x. So 2 + 2 + 2 = 6. Right before the 4th iteration, x < 5 is no longer true, so the loop exits. Problem 2: It is an infinite loop because x is always 0, which means x <= 3 is always true. This is because x *= 2 computes 0 * 2 = 0.
But while x<5 mean x=0,1,2,3,4 Why just 2+2+2?
While loop does not increase the x automatically, it is increasing by 2 because it is in the code 'x = x+2'
x increases by 2 each time because of `x = x + 2`. So the x values are not 0, 1, 2, 3.. but 0, 2, 4, 6
prloblem 1 If i share what i think about that is X=0+2, x=2+2 X=1+2, x=3+2 X=2+3, x=5+2 Like that???
For problem 1, X = 4+2 = 6 ( because our condition is x<5 so, lastly we have to consider x = 6 as our final answer.
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