How to make a First and last day of the Year ?

Question

var fullDate=new Date();
var Days=["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
var y=fullDate.getFullYear();
var m=fullDate.getMonth();

var first_day=new Date(y,m,1).getDay();
var TotDays=fullDate.getDate();

var StartDay=Days[first_day];
document.write("Start Day:"+StartDay+"<br>");

NumberOfDays=new Date(y,m+1,0).getDate();
var last=new Date(y,m,NumberOfDays).getDay();

document.write("End Day:"+Days[last]+"<br>");

Answer 1

JavaScript Get Date Methods

https://www.w3schools.com/js/js_date_methods.asp

Answer 2

var date = new Date();

var first=new Date(date.getFullYear(), 0, 1).toLocaleString("default", { weekday: "long" });

var last=new Date(date.getFullYear(), 11, 31).toLocaleString("default", { weekday: "long" });

Answer 3

#include <iostream>
using namespace std;

int leapcheck(int yr){
if(yr%400==0)
return 1;
else if(yr%100==0)
return 0;
else if(yr%4==0)
return 1;
else
return 0;

}
int main() {
int diff,year,nlp,d,val,d0=1,lp=0;
cin >> year;
diff=year-1; // taking year 1 as base case
for(int i=1;i<year;i++)
if(leapcheck(i)==1)
lp++;
nlp=diff-lp;
d=1+1*(nlp)+2*(lp); // d=d0+1*nlp+2*lp;
val=d%7;
switch(val){
case 1 :
cout << "1st day of the year " << year << " was Monday" << endl;
break;
case 2 :
cout << "1st day of the year " << year << " was Tuesday" << endl;
break;
case 3 :
cout << "1st day of the year " << year << " was Wednesday" << endl;
break;
case 4 :
cout << "1st day of the year " << year << " was Thursday" << endl;
break;
case 5 :
cout << "1st day of the year " << year << " was Friday" << endl;