Program to find whether the given year is leap year or not

Question

https://code.sololearn.com/ctd1NiW8aNjN/?ref=app

Answer 1

You have no proper braces.. ( ) for if block.
And it should be != , not just !.

edit:

public class leapyearexample
{
public static void main(String[] args) {
int year=2020;
if( ((year % 4==0)&&(year % 100 != 0))||(year % 400==0) ){
System.out.println("leap year");
}
else{
System.out.println("common year");
}
}
}

Answer 2

I already added corrected code.
edited and adding here.
You have missing one more pair of brace.
if👉( condition ) 👈

edit:
if( ((year % 4==0)&&(year % 100 != 0))||(year % 400==0) ){

Answer 3

Bro there are 3 more error

Answer 4

Ahmed Kazia Get used to always provide full info. Instead of "there are x errors", always tell which ones.