On Java practice 58.2 what is wrong ?

Question

import java.util.Scanner;
import java.util.InputMismatchException;

public class Main
{
public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

try {
int num1 = scanner.nextInt();
int num2 = scanner.nextInt();
/*
1. Еrror: division by zero
2. Error: wrong value type
*/
//your code goes here
System.out.println(num1/num2);
} catch(ArithmeticException ex) {
System.out.print("Error: division by zero ");

} catch(InputMismatchException ex){
System.out.println("Error: wrong value type");
}

}
}

// on #2
//Your output : Error: division by zero
//expected output: Error: division by zero
// same output. somehow failed.

Answer 1

You have an extra space at the end.

Answer 2

Hm. Try with "println" instead of "print".

Answer 3

Thank you. But failed again.

Answer 4

It failed. Sorry.

Answer 5

Now l succeeded by copy and paste the message written by the problem maker.

Answer 6

How was this solved?

Answer 7

By Copy and Paste the " Error: division by zero" .
This problem was Same appearance with different code.
Maybe l used an input system which can input Japanese.

Answer 8

Как это решить? Я не понимаю

Answer 9

You need to write a divider program which will operate with integers,
The program you are given should take two integers as input and execute the division, but we need to handle two exceptions:
1. the divider shouldn't be zero
2. both inputs should be integers.
Complete the program to handle them. For the first exception, the program should output "Mistake: division by zero"; and for the second one, "Mistake: wrong value type".

Sample Input
1
b

Sample Output
Mistake: wrong value type

Answer 10

My answer Working

import java.util.Scanner;
import java.util.InputMismatchException;

public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);

try {
int num1 = scanner.nextInt();
int num2 = scanner.nextInt();

if (num2 == 0) {
throw new ArithmeticException("Error: division by zero");
}

System.out.println(num1 / num2);

} catch (ArithmeticException e) {
System.out.println(e.getMessage());
} catch (InputMismatchException e) {
System.out.println("Error: wrong value type");
} finally {
scanner.close();
}
}
}