I need help

Question

Write a program that will find all numbers which are divisible by 7 but are not a multiple of 5, between
2000 and 3200 (both included). The numbers obtained should be printed in a list.

Answer 1

import java.util.Arrays;
public class Program
{
public static void main(String[] args) {

int count=0;
for (int i=2000;i<=3200;i++) {
if (i%5==0 || i%7!=0){
continue ;}
else{ count+=1;

}}
int[] list=new int[count] ;

int count1=-1;
for (int i=2000;i<=3200;i++) {
if (i%5==0 || i%7!=0){
continue ;}
else{ count1+=1;
list[count1]=i; }}

System.out.println (Arrays.toString (list));

}}

Answer 2

import util package
Or
import java.util.ArrayList;

Create arraylist. if you don't know, read arrayList lesson..
Instead of printing add to list like

if ( i%7==0 && i%5 != 0 )
arraylist.add(i);

After loop print list by
System.out.println(arraylist);

Hope it helps..

Answer 3

Your try?

Answer 4

public class Program
{
public static void main(String[] args) {
for(int i=2000; i<=3200;i++){
if ((i%7==0) ^ (i%5==0)){
System.out.println (i);
}
}

}
}

Answer 5

list=[]
for i in range(2000,3202):
if (i%5==0 or i%7!=0):
continue
else:
list.append(i)
print(list) #python

Answer 6

Thank you

Answer 7

i will try to do it python because training, if you want the code tell me

Answer 8

I want print result in a list

Answer 9

So how i can do it?

Answer 10

You're welcome...

Answer 11

How to make own logic programming

Answer 12

alright i see you liked my answer, i just did it here you go simple as that in python:
https://code.sololearn.com/cWPorlR4K6Hg/?ref=app

Answer 13

Rayan thanks bro

Answer 14

no problem

Answer 15

replying to you walid in the code i just liked:
i donknow java but there's a problem since you said "not a multiple of 5, then you don't write i%5 ==0 but i%5 != 0 because when you say i%5 == 0 it means i multiple of 5 and idk how to create a list in java so you have to create a list [ ] with nothing inside then list.append(i) then print(list) but in the java way 👍