There are two lists of objects, the first one is a list of the pets(their name,age,gender), the second is the owners’ list.

Question

How do i give an owner a pet? Meaning how do i for example link the first person in the owners’ list with the first pet in the pets’ list?Also remember that i have already made separate classes for each kind of pet,ie cats,birds,hamsters. Meaning the pets list can contain any kind of pet.

https://code.sololearn.com/c1PBlh8mYYRg/?ref=app

Answer 1

nested = {"Owner":
{"animal": "Cat",
"Gender":"Female",
"Age": 3},
"Owner2": {
"animal": "Dog"}}

print("owner1 = ", nested["Owner"])
print("owner2= ", nested["Owner2"])

Nested dictionary can look something like this you can easily update

Up to you to learn more about it

Answer 2

Jay Matthews attribute error

Answer 3

Jay Matthews what if i want the fist person in owners’ list to have the second pet in the pets’ list?

Answer 4

I should be able to manipulate who is going to own which pet

Answer 5

Create a nested dictionary

Answer 6

Jay Matthews to print out all the contents in l is it enough to print(l)?

Answer 7

Ion Kare the classes must be used in this case, owner1 for example owns a class ”cat” and the cat’s name, gender and age should be included in that list

Answer 8

Ion Kare how about:
A = {owner(”john”, ”doe”): cat(”catname”, ”male”, 4}

Answer 9

#A = {owner:(”john”, ”doe”)}, cat:{”catname”, ”male”, 4}
#print(A)

A = {"owner":
{"first": "john",
"last": "doe",
"cat":
{"catname": "swimmy",
"Gender": "Male"}},
# second owner
"owner2":{
"first": "tom",
"last": "mop"
}}

#print(f"{A['owner']}")
print(f"{A['owner']['cat']}")

print("\n\tfirst ^^^ | second vvv")

print(f"\n{A['owner2']}")

Could totally do something like that , its many ways you can solve this why not try jay way its easy and simple and less confusing

Answer 10

Jay Matthews wont do, it just says [[<__main__.owner object……

Answer 11

Ion Kare the ”owner” in the dictionary is not related to the class right?

Answer 12

Jay Matthews that just shows the owner

Answer 13

Jay Matthews Does l,n = [],[] create 2 lists at the same time?so i could have written l = [] then n = [] it would be the same as l,n = [],[] right?

Answer 14

Jay Matthews [],[] stands for lists though?

Answer 15

Jay Matthews What if the owner has many pets? Is it enough with print(a[0].name, a[0].lastname, a[1].name, a[1].gender, a[1].age)??

Answer 16

Jay Matthews like u said this adds owner1 and pet1 in first in n then later in l list
l,n=[],[]
n.append(owner1)
n.append(pet1)
l.append(n)
If i were to add another owner (owner2) and pet(pet2) the same way would list ”l” look something like this:
l = [[owner1, pet1],[owner2,pet2]]?

Answer 17

Jay Matthews Ok.Assuming petlist is full:
Owner1 = owner(”Johnny”, ”Johnson”, pets[0])
ownerlist.append(owner1)
Print(ownerlist.name, ownerlist.lastname, ownerlist.pets)
Gives me a typeerror: __str__() missing a 3 required positional arguments

Answer 18

Jay Matthews Even the loop has to be inside the def __str__() part?

Answer 19

Jay Matthews
def __str__(self,name,Lastname,pets):
print(self.name, self.gender, self.age)
For a in pets:
print(a.name, a.gender, a.age)
This one wont work, i got the same output as last time

Answer 20

Jay Matthews i updated the code if thats what u meant