WHy does this returns 4294967293 and not +3 since %u is used, i get the reason why 4294967293 yields but why not 3 , someone ple

Question

#include <stdio.h>
int main()
{
unsigned i = 1;
int j = -4;
printf("%u", i + j);

return 0;
}

Answer 1

Jayakrishna🇮🇳 how do you convert -3 to an unsigned integer?

Answer 2

There i+j result -3
Since you are expecting %u unsigned int then -3 is converted to unsigned value which is equal to what you getting...

Answer 3

/* Infinity
Generally negative values are stored by its complement form.
But to simplify it like :

Technically, 2^32 (IUNIT_MAX value) is added to it, where N is the number of bits used to represent the unsigned type.

In this case, since int on your platform has a width of 32 bits, -3 is subtracted from 2^32, yielding 4,294,967,293.
*/

#include <stdio.h>
#include <math.h>
int main() {

printf("%ld",(long)pow(2,32)-3);

return 0;
}

Answer 4

Jayakrishna🇮🇳 thanks, great explanation