Can anyone help me with this else and handling challenge bon appetit.

Question

I want to use my code but I don't understand why it is not working to catch a value error. Should I raise one? I'm confused here is my code...
code = input()

#your code goes here
try:
for i in code:
if i != int():
print("Order accepted")
print("Bon appetit")
break
except:
if i == int():
print("Enter only digits")

❤️ 🙏

Answer 1

Chelsie Herr ,

the input has to be taken inside the try:... block. use int(input()) so it will try to converted the input to int. if this conversion fails, because the input contains some other characters like letters, spaces,...
this causes the except: ... block to execute

try:
code = int(input())
print("Order accepted")
print("Bon appetit")
except: # this captures all errors
except ValueError: # or you can take this to capture only ValueErrors
print("Enter only digits")

Answer 2

If could hug 🫂 you! Lothar

Answer 3

Drop the code so it can be preview

Answer 4

😎👏