RePost: How to get the index posisition of name in a list tuple? "

Question

How to get the index posisition of name in a list tuple?

contacts= [
("James",42),
("Amy",24),
("John",31),
("Amanda",63),
("Bob",18)
]
#I want the user to give me a name, and then i want to check if that name is in the tuple and it should return the index posistion to a variable of the name in the tuple

#Also the index posistion of the name age in the tuple

#what i did was

name = input(#James)
if contacts [0][0] == name:
age = contacts[0][1]
print(name +" is "+ str(age))

#another problem is i don't know how to create a function that would create these indexs to find if the word is there or not

if anyone could just help me, with getting the index posistion inside of the tuple

Answer 1

def find(search_name, data):
for idx, (name, age) in enumerate(data):
if name == search_name:
return idx

There are multiple tricks here
- enumerate function associates the index position with each data element
- "for i, d in enumerate..." The index and the actual data is assigned to two different variables
- in this case each piece of data is a tuple of two elements, so it can further be destructured to variables: "for idx, (name, age)"
- in addition to using the search name as argument, I am passing the contacts also. This is a principle of functional programming that a functions should not have any external dependencies apart from its arguments.

https://code.sololearn.com/cRSvvu609s2R/?ref=app

Answer 2

Even without knowing all the functions, you can achieve the result you need.
You just need to use a loop to iterate over the index of the list and correct your mistakes of course:

name = input()or"James"
loop☺️:
if contacts[i][0] == name:
age = contacts[i][1]
print(name +" is "+ str(age))

Answer 3

Simba, you forgot to change grade to j, but it's better to fix both on age ☺️

Answer 4

Why don't you use a dictionary? Your data seems to have been made for that.

Answer 5

Paul, in your case the condition is no longer needed:
contacts = dict(contacts)
print(name, "is", contacts.get(name))

Answer 6

You can also do it like this

name = input()
for i,j in contacts:
if i == name:
print(i ,"in",j)
break
else:
print("Not found")

Answer 7

#Your way :

contacts= [
("James",42),
("Amy",24),
("John",31),
("Amanda",63),
("Bob",18)
]
name = input()
for i in range(len(contacts)) :
if contacts[i][0] == name:
age = contacts[i][1]
print(f"At index {i} : {name} is {age}")

Answer 8

Paul can you show me

Answer 9

Something like this, it doesn't work with id's but i don't understand why you want that anyway:

contacts= [
("James",42),
("Amy",24),
("John",31),
("Amanda",63),
("Bob",18)
]
name = input()
contacts = dict(contacts)
if name in contacts:
print(name + " is " + str(contacts[name]))
else:
print(name + " not found")

Answer 10

#And @solo further, not to return none for input :

contacts = {
"James" : 42, "Amy" : 24, "John" : 31,
"Amanda": 63, "Bob" : 10
}

name = input()

print(name + " is " + str( contacts.get( name, "not found" )))