Making Coffee Question, need help!

Question

'''Need help
3 test pass but 1 fail '''

coffee = ["Café Latte", "Caffe Americano", "Espresso", "Cappuccino", "Macchiato"]

choice = int(input())

try:
#your code goes here
if choice in range(0,5):
print (coffee[choice])
except:
#and her
print("Invalid")
finally:
#and finally here
print("Have a good day")

Answer 1

You need to print "Invalid number".

And I think this part is not necessary:
if choice in range(0,5):
I mean you have try: So you don't need to make sure that the number is in range.

How I solved it:

coffee = ["Café Latte", "Caffe Americano", "Espresso", "Cappuccino", "Macchiato"]

choice = int(input())

try:
#your code goes here
print(coffee[choice])
except:
#and here
print("Invalid number")
finally:
#and finally here
print("Have a good day")

Answer 2

Sẩm Lâm Bảo Quý

Because of this line:
if choice in range(0,5):

Input is 8
if choice in range(0,5) gets false and nothing will happen.

The try part will not work so the except part is not executed.

Answer 3

Sẩm Lâm Bảo Quý

Just use except:
You need to catch all exceptions.
Because the input could also be a string which leads to an other exception than a number out of range.

Answer 4

I get it, but still 3 pass, 1 fail
Choice input = 8
Except not working

Answer 5

I have still google this things for a hour... jeez

Answer 6

#here the code pass...jeez I did it
coffee = ["Café Latte", "Caffe Americano", "Espresso", "Cappuccino", "Macchiato"]

choice = int(input())

try:
#your code goes her
print (coffee[choice])
except IndexError:
#and her
print("Invalid number")
finally:
#and finally here
print("Have a good day")

Answer 7

except IndexError