C++ Queue Management 3

Your Queue class is up and working in a customer service company. The company opens up a new branch and asks you to make another version of the Queue for them. The only difference is the way the Queue is displayed: each number on a new line. You decide to create a new class called Queue2, which is derived from the Queue class and overrides the print() method, outputting each element of the queue on a new line. Do not forget to change the access specifier of the Queue members, as they won't be inherited if private. #include <iostream> using namespace std; class Queue { int size; int* queue; public: Queue() { size = 0; queue = new int[100]; } void add(int data) { queue[size] = data; size++; } void remove() { if (size == 0) { cout << "Queue is empty"<<endl; return; } else { for (int i = 0; i < size - 1; i++) { queue[i] = queue[i + 1]; } size--; } } void print() { if (size == 0) { cout << "Queue is empty"<<endl; return; } for (int i = 0; i < size; i++) { cout<<queue[i]<<" <- "; } cout << endl; } Queue operator+(Queue &obj) { Queue res; for(int i=0;i<this->size;i++) { res.add(this->queue[i]); } for(int i=0;i<obj.size;i++) { res.add(obj.queue[i]); } return res; } }; //your code goes here int main() { Queue q1; q1.add(42); q1.add(2); q1.add(8); q1.add(1); q1.print(); Queue2 q2; q2.add(3); q2.add(66); q2.add(128); q2.add(5);q2.add(111);q2.add(77890); q2.print(); return 0; } I am lost, could someone explain why & what to do?

21st Oct 2021, 4:30 PM
Alex Ramsey
1 Answer
At this point you have a Queue class. Now define a new class named Queue2 that is a subclass of Queue. In Queue2 add a print() method that prints all the contents of queue. The difference between the new overriding print method and the original one is that the new one adds a newline.
21st Oct 2021, 4:56 PM
Brian - avatar