C++ Queue Management 3

Question

Your Queue class is up and working in a customer service company. The company opens up a new branch and asks you to make another version of the Queue for them. The only difference is the way the Queue is displayed: each number on a new line.
You decide to create a new class called Queue2, which is derived from the Queue class and overrides the print() method, outputting each element of the queue on a new line.
Do not forget to change the access specifier of the Queue members, as they won't be inherited if private.
#include <iostream>
using namespace std;
class Queue {
int size;
int* queue;
public:
Queue() {
size = 0;
queue = new int[100];
}
void add(int data) {
queue[size] = data;
size++;
}
void remove() {
if (size == 0) {
cout << "Queue is empty"<<endl;
return;
}
else {
for (int i = 0; i < size - 1; i++) {
queue[i] = queue[i + 1];
}
size--;
}
}
void print() {
if (size == 0) {
cout << "Queue is empty"<<endl;
return;
}
for (int i = 0; i < size; i++) {
cout<<queue[i]<<" <- ";
}
cout << endl;
}
Queue operator+(Queue &obj) {
Queue res;
for(int i=0;i<this->size;i++) {
res.add(this->queue[i]);
}
for(int i=0;i<obj.size;i++) {
res.add(obj.queue[i]);
}
return res;
}
};
//your code goes here
int main() {
Queue q1;
q1.add(42); q1.add(2); q1.add(8); q1.add(1);
q1.print();
Queue2 q2;
q2.add(3); q2.add(66); q2.add(128); q2.add(5);q2.add(111);q2.add(77890);
q2.print();
return 0;
}
I am lost, could someone explain why & what to do?

Answer 1

At this point you have a Queue class. Now define a new class named Queue2 that is a subclass of Queue.
In Queue2 add a print() method that prints all the contents of queue. The difference between the new overriding print method and the original one is that the new one adds a newline.