+ 1

# Lists python

#a=1 b=2 c=3 d=4 e=5 f=6 g=7 h=8 i=9 j=10 k=11 l=12 m=13 n=14 o=15 p=16 q=17 r=18 s=19 t=20 u=21 v=22 w=23 x=24 y=25 z=26 list = ["i", "you", "everyone", "love", "coding"] print(max(list)) #you print(min(list)) #coding In which bases max and min of list (strings) are decided?

8th May 2021, 6:11 AM
Pranav Hirani
+ 6
For strings max / min of list are decided by their ASCII values. Like here : ASCII value of i = 105 ASCII value of y=121 ASCII value of e=101 ASCII value of l=108 ASCII value of c=99 So from above data u can see that max ASCII value is of y and min is of c.
8th May 2021, 6:36 AM
Kǟrɨsɦmǟ ❥
+ 3
String are compared sequentially from first char to last char. (Not by length ) "S" , "ABC" when we compare these 2 strings => at first Both 1st char of strings is compared .here "s" > "a" so "s">" abc" . When both char gets equaled then comparison done comparing 2nd char,.... Like this . if both 2nd char are equal then 3rd char ... then 4th etc "abcf" "ac" here both first char is equal so it compares 2nd char . as "c">" b" so "ac" > "abcf"
8th May 2021, 6:32 AM
TOLUENE
+ 1
Why only by first letter?
8th May 2021, 6:14 AM
Pranav Hirani
+ 1
Here in your list max value of first char is 'y' and min value is 'c' So you get max => you min => coding.
8th May 2021, 6:36 AM
TOLUENE
8th May 2021, 6:39 AM
Pranav Hirani