Casting from a char to int

Question

Never work this code no matter what I use
It does not work
import java.util.Scanner;
class Main {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
char a = read.next().charAt(0);
// int c= Integer.toString(a).charAt(0);
// int c = Integer.parseInt(a);
// int c = (int) a.charAt(0);
// int c = (char) (a+1);
// int c = Character.getNumericValue(a);
int c = Integer.parseInt(String.valueOf(a));
//int c = a;
// a = (c);
int c = (int) a.charValue()
System.out.println(c);
//your code goes here
}

Answer 1

char a = '3';
char b = '4';
int c = Character.getNumericValue(a);
int d = Character.getNumericValue(b);
int r = c + d;
System.out.println(r);

Answer 2

Hello,
Please to see your problem would like to discuss here might be it is helpful
It seems like there are some errors and inconsistencies in the code you provided. Here's a modified version of the code that should work as expected:
java
Copy code
import java.util.Scanner;
class Main {
public static void main(String[] args) {
Scanner read = new Scanner(System.in);
char a = read.next().charAt(0);
int c = (int) a; // convert char to int
System.out.println(c);
}
}
The Scanner class is used to read input from the console. The next() method reads the input as a String, and charAt(0) gets the first character of the input string.
To convert the char variable a to an int, we can simply cast it to an int. The value of the char is its Unicode value, so the resulting int value will be the Unicode value of the character.
Finally, we print the value of c using the System.out.println() method.
If you still face any issues, please provide more details on what exactly you are trying to achieve and what error messages you are seeing.
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Answer 3

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