PASSWORD VALIDATION

Question

'''
Task:
Write a program that takes in a string as input and evaluates it as a valid password. The password is valid if it has at a minimum 2 numbers, 2 of the following special characters ('!', '@', '#', '

Answer 1

《 Nicko12 》 Thanks for your input brother. You explained 2 vital concepts needed to solve this challenge.
(I) Order
(ii) seperated test cases
With the help of these inputs, I have finally solved this challenge.
My code is -
password = input()
import re
pattern1 = r".*[0-9]+.*[0-9]+.*"
pattern2 = r".*[[email protected]#$%&*]{1}.*[[email protected]#$%&*]{1}.*"
if len(password)>=7 and re.search(pattern1,password) and re.search(pattern2,password):
print ("Strong")
else:
print ("Weak")
Thanks a lot!!!

Answer 2

password = input()
import re
pattern1 = r"[0-9]{2,}"
pattern2 = r"[[email protected]#$%&*]{2,}"
if len(password)>=7 and re.search(pattern1,password) and re.search(pattern2,password):
print ("Strong")
else:
print ("Weak")
# Patterns are seperated so that it will just search for numbers and symbols regardless of the order. The reason why your pattern does not work in other test cases is because the condition will only become true if the number comes first before the symbol.

Answer 3

CHANDAN ROY
Oh ok, maybe the reason is the last test cases' number or symbol have letters in between i.e. , seperated. Try this:
password = input()
import re
pattern1 = r"[0-9]"
pattern2 = r"[[email protected]#$%&*]"
if len(password)>=7 and len(re.findall(pattern1,password)) >= 2 and len(re.findall(pattern2,password)) >= 2:
print ("Strong")
else:
print ("Weak")
# re.findall creates a list containing elements that satisfy the pattern. We used "len" method to know how many numbers or symbols are there.

Answer 4

CHANDAN ROY
Hello2wo#[email protected]

Answer 5

《 Nicko12 》 That explanation was really helpful and it did solve one of the two tests that I had failed.
Most importantly, I learnt something I had missed in the lesson though it was explained there.
So, thanks a lot!!
It still fails one last hidden condition.

Answer 6

I Am AJ ! 《 Nicko12 》

Answer 7

《 Nicko12 》 Give an example of what you just said in opening line of your previous comment "maybe the reason is the last test cases number of symbol have letters in between I.e.,seperated."

Answer 8

is this not working? I tried this and the problem is solved.
https://code.sololearn.com/ccwGiV7xykIi/?ref=app

Answer 9

import re
s = input()
if len(s) >= 7:
pattern = r"[0-9].*[0-9]"
if re.search(pattern, s):
pattern = r"[[email protected]#$%&*].*[[email protected]#$%&*]"
if re.search(pattern, s):
print('Strong')
else:
print('Weak')
else:
print('Weak')
else:
print('Weak')

Answer 10

Works like a charm 😊
i = list(input())
sc = list("[email protected]#$%&*")
n = list("0123456789")
cSc = 0
cN = 0
for x in i:
if x in sc:
cSc += 1
if x in n:
cN += 1
if cSc >= 2 and cN >= 2 and len(i) >= 7:
print("Strong")
else:
print("Weak")

Answer 11

import re
password = input()
symbols_list = re.findall('[[email protected]#$%&*]', password )
number_list = re.findall("[0-9]", password )
if len(password) >= 7 and len(symbols_list ) >= 2 and len(number_list )>=2:
print("Strong")
else:
print("Weak")

Answer 12

[phone]