can any one explain how the out put comes for this code:

Question

Sorry for not posting full code
this is full code :
#include <iostream>
using names pace std;
int main (){
int i=0;
while(i++<5){
int j=i;
while(j<3)
cout<<j++<<endl;
cout<<endl;
}
return 0;
}

Answer 1

This code don't output anything else than a compilation error, because of the missing semi-colon at firstline... even if you encapsulte it in a main() fonction ( for make the code valid ).
After correction ( not evident with no indentation, and curly brakets not always present: it's valid, but not evident if the missing is wanted or not ), the output is:
1
2
2
Correct ?
Anyway, the "difficulty" here is in how works incrementation between post and pre ( i++ and ++j ). Well, it's just logical:
i++ --> value of i is used before i modified ( reading direction: first i, second incrementation )
++j --> value of j modified before j used ( reading direction: first incrementation, second j )
So, in your code, i is tested before incrementation, and j is tested after incrementation...

Answer 2

can u post the complete code pls?