Reverse the strings in a list and sort them

Question

How can I use the following functions to reverse the strings in a list and then sort in alphabetical order? I have some problems in the following functions, and I’m grateful for any help.

def my_sort(lst):
return sorted(lst, key=reverse_str_sort)

def reverse_str_sort(s):
#type(s) is a string
return reverse_str

Here is the sample:
#input:
lst=["apple","btc","python"]
#output:
["btc","apple","python"]

Answer 1

def sort(lst):
return sorted(lst)

def reverse_sort(lst):
#type(s) is a string
return sorted(lst, reverse=True)

#input:
lst=["apple","ztc","python"]
print (lst)
#sorted:
print (sort (lst))
#reverse:
print (reverse_sort (lst))

Answer 2

I don't understand the difference you make between 'to order' and 'to sort' ? Sorry 😯.

Answer 3

Ok, no problem Vicky.
Try this :
https://code.sololearn.com/cvL6Zt6hir7I/?ref=app

Answer 4

Oww.. sorry! I typed totally wrong and made you so confused. :(
I meant the output has to be in alphabetical order after being reversed the strings.
For example, input a list: lst=[hi, app, candy]
Reverse the strings and become: [ih, ppa, ydnac]
So final output should be: [hi, app, candy].
Does this make sense? >_<

Answer 5

@Geo thank you for your generosity!! :)
I referred to your code and found another way to solve it :)
Here is my code after revising yours:

def reverse_str_sort(s):
return s[::-1]
def my_sort(lst):
return sorted(lst, key=reverse_str_sort)
lst=["apple","btc","python"]

my_sort(lst)

Answer 6

But actually I don’t really understand why I don’t need to define the argument “s” and the functions still can work...